5y^2-95y+95=0

Solution for 5y^2-95y+95=0 equation:

5y^2-95y+95=0

a = 5; b = -95; c = +95;
Δ = b2-4ac
Δ = -952-4·5·95
Δ = 7125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7125}=\sqrt{25*285}=\sqrt{25}*\sqrt{285}=5\sqrt{285}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-5\sqrt{285}}{2*5}=\frac{95-5\sqrt{285}}{10}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+5\sqrt{285}}{2*5}=\frac{95+5\sqrt{285}}{10}
$